If triangle ABC and DEF are similar , AM and DN are Median of triangle ABC and DEF respectively , Prove that AB/DE= AM/DN
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AB/DE = AM/DN
Given:
ABC and DEF are similar , AM and DN are Median of triangle ABC and DEF respectively.
To find:
Prove that AB/DE= AM/DN
Solution:
Given that ∆ABC and ∆ DEF are similar
AB/DF = BC/EF = AC/DF (1)
<A = <D
<B = <F (2)
<C = <F
BC = 2BM
EF = 2EN
2BM/2EN = AB/DE
BM/EN = AB/DF (3)
<ABM = <DEN
Then from equation 3 and 4
∆ABM is similar to ∆DEN
AB/DE = BM/EN = AM/DN
AB/DE = AM/DN
Conclusion:
Proved that AB/DE = AM/DN
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