Question

if triangle abc and right angled atc what is the value of​

Answer 1

Answer:

not defined

Step-by-step explanation:

in triangle ABC

\angle A + \angle B + \angle C = 180^\circ∠A+∠B+∠C=180

∘

....1

(angle sum property)

then it is given that \angle C = 90^\circ∠C=90

∘

putting the value of C in equation 1

we get

\begin{lgathered}\angle A + \angle B + 90^\circ= 180^\circ\\\angle A + \angle B= 180^\circ -90^\circ\\\angle A + \angle B= 90^\circ\\\end{lgathered}

∠A+∠B+90

∘

=180

∘

∠A+∠B=180

∘

−90

∘

∠A+∠B=90

∘

now ,

sec (A+B) = sec 90°

sec 90° = \frac{1}{cos 90}

cos90

1

= \frac{1}{0}

0

1

= not defined

hence ,

The value of sec(A+B) is not defined

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Answer 2

Answer:

Can you tell me What is the value of ________ .

So, I will help you. OK

Step-by-step explanation:

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