if triangle ABC and triangle DBC isosceles on same base BC then
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To Prove: ∆ABC ≅ ∆ABD. Given: In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. ... Given: ∆ABC and ∆DBC are twoisosceles triangles on the same base BC and vertices A and D are on thesame side of BC. AD is extended to intersect BC at P.
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