Question

If triangle ABC and triangle DEF are similar such that 3AB =DE and BC=6cm then EF is ???​

Answer 1

$As, \: triangle \: ABC \: and \: DEF \: are \: similar .....  \\ \: and \: DE = 2AB \: and \: BC = 8 cm ......... \\ </p><p> \\ </p><p>then \: according \: to \: sides \: theorem :- \\ </p><p></p><p> \frac{AB}{DE} = \frac{BC}{EF} \\ </p><p></p><p> = > \frac{AB}{2AB} = \frac{BC}{EF} .......... [as DE = 2AB] \\ \\ </p><p></p><p> = > \frac{1}{2} = \frac{BC}{EF} \\ </p><p></p><p> = > EF = 2BC \\ </p><p></p><p> = > EF = 2 \times 8 = 16 cm .........(ans) ... \\ \\ </p><p></p><p>Hope \: this \: helps !!$

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