if triangle ABC and triangle DEF are similar such that angle A= 50 angle E=80 then angle C =
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sum of all angles of a triangle is 180 degree so angle c.... will be 50 degree...
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Answer:
∠C = 50°
Step-by-step explanation:
∠A = 50°
∠E = 80°
Now, ΔABC ≅ ΔDEF (ATQ)
So,
∠A = ∠D = 50°
∠B = ∠E = 80°
Now,
∠A + ∠B + ∠C = 180° (A.S.P of Δs)
∠C = 180° - (∠A+∠B)
=)∠C = 180° - (50° + 80°)
=)∠C = 180° - 130°
=)∠C = 50°
Hence, ∠C = 50°
Thank You
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