if triangle abc angel a +b=108and angle b and c =130 find all angle
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Answered by
5
a+b=108
c+b=130
a=180-n
c=130-b
sun of all angles in a triangle =180
So,
180-b+130-b+b (a+b+c)
238-b=180
238-180=b
58
Therefore.
a=108-58
50
b=58
c=130-58
72
c+b=130
a=180-n
c=130-b
sun of all angles in a triangle =180
So,
180-b+130-b+b (a+b+c)
238-b=180
238-180=b
58
Therefore.
a=108-58
50
b=58
c=130-58
72
Answered by
2
hope you understand it
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