If triangle abc ,angle a=90°a=25,b=7then find angle b and angle c in all trigonometry
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angle A = 90° and angle B 30°
=> angle C = 90° - 30° = 60°
=> BC is the hyp = 8 cm long
AC = 8/2 =4cm (sin30° = AC/hp => 8sin30°=AC
AC = 8×1/2 = 4
AB = √(BC^2 - AC^2) = √(8^2 - 4^2) = √(64-16) = 6.93cm
AC = 4 cm
AB = 6.93 cm
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=> angle C = 90° - 30° = 60°
=> BC is the hyp = 8 cm long
AC = 8/2 =4cm (sin30° = AC/hp => 8sin30°=AC
AC = 8×1/2 = 4
AB = √(BC^2 - AC^2) = √(8^2 - 4^2) = √(64-16) = 6.93cm
AC = 4 cm
AB = 6.93 cm
please mark me as a brainliest
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