If triangle ABC angle A is,90 drgeee ,ab equal to 6cm ,bc= 10cm and ac = 8cm find the radius
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In right triangle BAC
BC2 = AB2 + AC2 [By Pythagoras theorem]
= 62 + 82
= 36 + 64
= 100
Hence BC = 10 cm
Semi-perimeter, s = (a + b + c)/2
= (6 + 8 + 10)/2 = 12 cm
Area of right triangle ABC = (1/2) x AB x AC
= (1/2) x 6 x 8 = 24 sq cm
We know that, area of triangle, Δ = r x s
That is 24 = r x 12
Therefore r = 2 cm.......
BC2 = AB2 + AC2 [By Pythagoras theorem]
= 62 + 82
= 36 + 64
= 100
Hence BC = 10 cm
Semi-perimeter, s = (a + b + c)/2
= (6 + 8 + 10)/2 = 12 cm
Area of right triangle ABC = (1/2) x AB x AC
= (1/2) x 6 x 8 = 24 sq cm
We know that, area of triangle, Δ = r x s
That is 24 = r x 12
Therefore r = 2 cm.......
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