Question

if triangle abc , e & f are the point on ab & ac respectively such that fe parallel to bc and fe divides the triangle is two parts of equal area .If ad perpendicular bc and ad intersects be at g , gd:ag=?

Answer 1

Answer:

1:1

Step-by-step explanation:

according to mid point theorem, if any line is parallel to the base and divides the triangle into 2 parts of equal area, it must pass through the midpoint of its 2 intersecting points,

hence, e and f both are quidistant from a and bc

then, by, theorem on intercepts,

if a transversal makes equal intercepts on three or more parallel lines, then any other line passing will also make equal intercepts,

parallel lines: l, ef, bc

transversal: ab, ac

hence, ag=gd

ag:gd=1:1