if triangle ABC equals to triangle efd , angle a 40 degree and angle f 65 degree than find b
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Answer:
In △ABC and △DEF,
∠A=∠E=40
∘
ED
AB
=
EF
AC
Thus, △ABC∼△DEF (SAS rule)
or ∠C=∠F=65
∘
Now, In △ABC,
∠A+∠B+∠C=180 (Sum of angles of triangle)
40+65+∠B=180
∠B=180−105
∠B=75
∘
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