Question

If triangle ABC has ✓ B = ✓ A + ✓ C ÷ 2 and ✓A: ✓C = 1: 2 then find the measure of each angle of triangle ABC.​

Answer 1

Answer:

I hope this is not sign of square root but sign to represent angle

B = (A+C)/2

A:C = 1:2

let A= k, C = 2k

B = (k + 2k)/2

= 3k/2

now

A+B+C = 180°

k + 3k/2 + 2k = 180

(2k + 3k + 4k)/2 = 180

9k/2 = 180

9k = 180*2

k. = 180*2/9

k = 40°

angle A = k = 40°

angle B = 3k/2 = 3*40/2 = 60°

angle C = 2k = 2*40 = 80°