Question

if triangle ABC,if angleB is 90⁰,sinA=3/5,then the value of cosC is​

Answer 1

Answer:

4/5

Step-by-step explanation:

sinA =3/5=length/diagonal

so AB=3 AC=5 BC=?

BC²+AB²=AC²

BC²=AC²-AB²=5²-3²=25-9=16

BC=√16=4

COS C=base/diagonal =4/5

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