if triangle ABC is a right angle at c then what is cos A + B
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Step-by-step explanation:
We know that a ""right angled triangle"" is a triangle in which one angle is “90°”
Given: ABC is a right angled triangle,
i.e. A+B +C = 90⁰,
Therefore A + B =180⁰ -C,
=180⁰- 90⁰,
A +B=90⁰,
Adding Cos on both the sides [In a right angled triangle the ""cosine or cos of an angle"" is the length of side which is adjacent divided by the length of hypotenuse],
Cos(A + B)=Cos(90⁰),
=0,
HOPE IT HELPS YOU.
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