if triangle ABC is an isosceles triangle in which AC, prove that the perpendicular from the vertices and C to their opposite side are equal
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Answer: AB=AC (GIVEN)
IN Δ ABE AND Δ ACF
∠A = ∠A (COMMON)
∠AEB = ∠AFC (EACH 1∠RT)
AB = AC (GIVEN IN QUESTION AND Δ ABC IS ISOSCELES TRIANGLE WITH AB=AC)
HENCE BY A.A.S.(ANGLE ANGLE SIDE CONGRUENCE RULE)
Δ ABE ≅ Δ ACF
∴ BY CPCT WE CAN SAY THAT CF = BE
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