Math, asked by narayana2789, 7 months ago

if triangle ABC is an isosceles triangle in which AC, prove that the perpendicular from the vertices and C to their opposite side are equal​

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Answered by harkaur0130
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Answer: AB=AC (GIVEN)

IN Δ ABE AND Δ ACF

∠A = ∠A (COMMON)

∠AEB = ∠AFC (EACH 1∠RT)

AB = AC (GIVEN IN QUESTION AND Δ ABC IS ISOSCELES TRIANGLE WITH AB=AC)

HENCE BY A.A.S.(ANGLE ANGLE SIDE CONGRUENCE RULE)

Δ ABE ≅ Δ ACF

∴ BY CPCT WE CAN SAY THAT CF = BE

MARK AS BRAINLIEST

HOPE IT HELPS ∪

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