if triangle ABC is an isosceles triangle such angle ab = angle ac then
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(i) In ΔABC, we have,
∴ AB = AC
[Given]
∠C = ∠B
[Angle opposite to equal sides are equal]
or ∠OCB = ∠OBC
⇒ OB = OC
[Sides opposite to equal angles are equal]
(ii) In ΔABO and ΔACO, we have
AB = AC
[Given]
OB = OC
[Proved]
∴ Using SAS criteria,
ΔABO ≌ ΔACO
⇒ ∠OAB = ∠OAC
[By CPCT]
⇒ AO bisects ∠A.
ΔABC is an isosceles triangle. ⇒ Their corresponding parts are equal. (ii) AB = AC, i.e. ABC is an isosceles triangle. ∴ Their corresponding parts are equal.
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