If triangle ABC is an isosceles triangle with AB=AC,what can you say about angle B and angle C
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According to the question, AB = AC
So, angle B = angle C (Since angles opposite to equal sides are equal.)
Angle B = 40 degree = Angle C.
Sum of all angles = Angle A + Angle B + Angle C
180 = Angle A + 40 + 40
180 - 80 = Angle A
So, angle A = 100 degree
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