if triangle ABC is congruent to triangle d e f and angle A equal to 50 degrees and angle F is equal to 60 degrees .then find Angle B
Answers
Answered by
24
ABC ≈DEF
∠A=√D=50
Than √F=√C=60
So -A+B+C=180
=50+B+60=180
=B=180-110
B=70
√B=√E=70
I hope you understand
my friend
∠A=√D=50
Than √F=√C=60
So -A+B+C=180
=50+B+60=180
=B=180-110
B=70
√B=√E=70
I hope you understand
my friend
Answered by
34
Hi.
Good Question...Keep Progressing...
Here is your answer---
Given---
Δ ABC is congruent to ΔDEF
Thus,
By CPCTC [Corresponding Parts of Congruent Triangles are Congruent].
∠ A = ∠ D = 50°
∠ B = ∠ E
∠ C = ∠ F = 60°
Now,
Using the angle sum property,
∠A +∠B + ∠C = 180°
50° + ∠B + 60° = 180°
110° + ∠ B = 180°
∠ B = 180° - 110°
∠ B = 70°
Thus, the value of the ∠B is 70°.
_______________________________________
_______________________________________
Hope it helps.
Please mark this answer as Brainliest.
Have a nice day.
Good Question...Keep Progressing...
Here is your answer---
Given---
Δ ABC is congruent to ΔDEF
Thus,
By CPCTC [Corresponding Parts of Congruent Triangles are Congruent].
∠ A = ∠ D = 50°
∠ B = ∠ E
∠ C = ∠ F = 60°
Now,
Using the angle sum property,
∠A +∠B + ∠C = 180°
50° + ∠B + 60° = 180°
110° + ∠ B = 180°
∠ B = 180° - 110°
∠ B = 70°
Thus, the value of the ∠B is 70°.
_______________________________________
_______________________________________
Hope it helps.
Please mark this answer as Brainliest.
Have a nice day.
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