Question

If triangle ABC is congruent to triangle QRP and angle A= 60, angle B= 45° then angle P=?​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

as ∆ABC ~= ∆QRP

angle A=Q

angle B= R

angle C=P. (i})

as a+b+c=180°. (ASP)

105°+c=180°

c= 75°

as C=P ( using i {cpct})

angle p= 75°