Question

If triangle ABC is congruent to triangle QRP and angle A= 60, angle B= 45° then angle P=? .​

Answer 1

Answer:

p= 75 degrees

Step-by-step explanation:

A=Q

B=R

C=P

A+B+C= 180

60+45+C=180

C=180-105

C=75

P=75. (:. C=P)

Answer 2

Given:

angle A= 60, angle B= 45°

To find:

Angle P

Solution:

As we know in the congruency the sides of the triangle are equal as per the sequence of the vertex is written in the congruency

as we have given:

ΔABC is congruent to ΔQRP

So,

• ∠A = ∠Q
• ∠B = ∠R
• ∠C = ∠P

from the angle sum property of the triangle

• ∠A + ∠B + ∠C = 180°
• 60°+45°+∠C = 180°
• ∠C = 180°-105°
• ∠C = 75°

so the value of ∠P is also 75°

∠P = 75°