if triangle ABC is congruent triangle DEF and angle A =50°,,angle F=60°then find angle B
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Since, ∆ ABC is congruent to ∆ DEF
Therefore, angle A= angle D { 50 ° }
B = C
C=F {60°}
Now in ∆ABC using ASP
A+B+C=180°
50°+B+60°=180°
B+110°=180°
B=70°{ans.}
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