if triangle ABC is congrunt triangle DEF and angle A= 50°, angle F=60° then find angle B
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Answered by
31
since ABC is congruent to DEF
angle A = ang. D
ang. B = ang. E
ang C = ang. F..... (i)
by CPCT
also ang ( A + B + C) = 180
50 + B + C = 180
from (i)
50 + B + 60 = 180
110 + B = 180
B = 70
angle A = ang. D
ang. B = ang. E
ang C = ang. F..... (i)
by CPCT
also ang ( A + B + C) = 180
50 + B + C = 180
from (i)
50 + B + 60 = 180
110 + B = 180
B = 70
Answered by
18
heya
here is ur answer
_______________________________
given :- ∆ABC is congruent to ∆DEF
so by CPCT
<A= <D
< B = <E
<C = <F
so in ∆ABC
<A = 50°
<C = <F =60°
<B= ?
v all know that sum of interior angles of a triangle is equal to 180°
so
<A+ <B + <C = 180°
50° +. <B + 60° = 180°
<B + 110° = 180°
<B = 180° - 110°
<B = 70°
____________________________
hope this helps u
here is ur answer
_______________________________
given :- ∆ABC is congruent to ∆DEF
so by CPCT
<A= <D
< B = <E
<C = <F
so in ∆ABC
<A = 50°
<C = <F =60°
<B= ?
v all know that sum of interior angles of a triangle is equal to 180°
so
<A+ <B + <C = 180°
50° +. <B + 60° = 180°
<B + 110° = 180°
<B = 180° - 110°
<B = 70°
____________________________
hope this helps u
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