if triangle ABC is congurant to triangle QRP ar(triangle ABC)/ar(triangle QRP) =9/4,BC is 15 cm then find the length of PR
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Answer:
Given :
Area of ∆ ABCArea of ∆QRP = 94
AB = 18 cm , BC = 15 cm So PR = ?
We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.
Area of ∆ ABCArea of ∆ QRP = AB
2
QR
2
= Bc
2
PR
2
= AC
2
QP
2
So, we take
Area of ∆ ABC Area of ∆ QRP = BC
2
PR
2
Now substitute all given values and get
94 = 152PR2
Taking square root on both hand side, we get
32 = 15PR
PR = 10 cm
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