Question

If triangle ABC is isosceles with AB = AC and circle (o, r) is the incircle of triangle ABC touching BC at L, prove that L bisects BC.

Answer 1

Solution: In the Triangle ABC, AB=BC, therefore, ½ <C= ½<B, => <OCI=<OBI (since, OB bisects angle B and OC angle C).

In the triangle, OBI and OCI, <OIB=<OIC (radius is always perpendicular to the circle’s tangent), <OCI=<OBI (proved earlier), OI=OI (Common).

Hence, given triangles are congruent through AAS. Hence, BI=CI (by CPCT) or I bisect line BC.

Answer 2

Answer:

Step-by-step explanation:

Solution: In the Triangle ABC, AB=BC, therefore, ½ <C= ½<B, => <OCI=<OBI (since, OB bisects angle B and OC angle C).

In the triangle, OBI and OCI, <OIB=<OIC (radius is always perpendicular to the circle’s tangent), <OCI=<OBI (proved earlier), OI=OI (Common).

Hence, given triangles are congruent through AAS. Hence, BI=CI (by CPCT) or I bisect line BC.

Read more on Brainly.in - https://brainly.in/question/8368349#readmore