Question

If triangle abc is light angle at c then the volue of sec (a+b) is

Answer 1

Answer:

Question 1:

A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m

and AD = 8 m. How much area does it occupy?

Solution 1:

Let us join BD.

In



BCD, applying Pythagoras theorem,

BD2 = BC2 + CD2

= (12)2 + (5)2

= 144 + 25

BD2 = 169

BD = 13 m

Area of



BCD =

1 1 2 2 BC CD 12 5 30

2 2

m m

 

         

For



ABD,

Perimeter (9 8 13) m 15 m

2 2

s

 

  

By Heron’s formula, Area of triangle =

s s a s b s c ( )( )( )   

Area of



ABD =

2

15(15 9)(15 8)(15 13) m   

2

 15(6)(7)(2) m 2

 6 35 m 2

  (6 5.916) m2

 35.496 m

Area of the park = Area of



ABD + Area of



BCD

= 35.496 + 30 m2

Step-by-step explanation:

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Answer 2

Answer:

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