Question

If triangle ABC, is right angled at B, then : (a) AB = AC (b) AC < AB (c) AB = BC (d) AC > AB

Answer 1

$\pink{Answer:}$

In a right angle triangle by pythagoras theorem

AB²+BC²=AC²

As AC is sum of square of two sides its greater.

hence AC >AB and AC>BC

hence answer is (d) and (c)

$\bold\red{Answer=option(d)(c)}$

hope it helps

Answer 2

Given that, triangle ABC is right angled at B.

Then, the side opposite to right angle is the longest side i.e. AC.

So, AC is the longest side and either of AB and BC  is the base or the other is the perpendicular.

(a) AC cant be equal to AB as AC is the longest side.

(b) AC cant be smaller than AB

(c) AB can be equal to BC is the triangle is a right-isosceles triangle where the perpendicular is equal to the base.

(d) AC is obviously larger that AB as we already proved it to be the longest side.

So, option c & d are correct.