Question

If Triangle ABC is right angled at C then find the value of sec a + b

Answer 1

Answer:

sec a+ b =sec 90 = not defined

Step-by-step explanation:

a+b = 180°+c= 180-90=90°

sec (a+b) =sec 90° = not defined

Answer 2

Answer:

∞

Step-by-step explanation:

The triangle ABC is given, which is a right-angled triangle with ∠C  is equal to 90°.

We know that the sum of all three angles of a triangle is always 180°.

Hence, for ΔABC, ∠A+∠B+∠C =180°

Given ∠C=90°, hence, ∠A+∠B=180°-90° =90°.

We have to find the value of Sec(∠A+∠B).

Hence, Sec(∠A+∠B) = Sec 90° =1/ Cos 90°=1/0=∞. {Since Cos 90°=0}

Therefore, Sec(∠A+∠B)= ∞ (Answer)