Question

If triangle ABC is right angled at C, then the value of sec (A+B) is​

Answer 1

Answer:

Not defined

Step-by-step explanation:

If C=90 then A+B=90 ( angle sum property of triangle)

sec(A+B)=sec90=which is not defined so

Answer 2

Given: Triangle ABC is right angled at C.

To find: The value of sec (A + B).

Answer:

(Diagram for referrence attached below.)

∠C = 90º

We know that the sum of all angles in a triangle must be 180º.

It is only fair if ∠A + ∠B = 90º.

Substituting this in sec (A + B),

sec 90° = $\frac{1}{cos\ 90 ^{\circ} }$

sec 90º = $\frac{1}{0}$, which isn't defined.

Hence, the value of sec (A + B) isn't defined.