Question

If triangle ABC is right angled at C, then the value of sec (A+B) is


a} 0
b] 1
c}2/√3

d} not defined

Answer 1

Hey mate

sec a+ b =sec 90 = not defined

Step-by-step explanation:

a+b = 180°+c= 180-90=90°

sec (a+b) =sec 90° = not defined

Hope this will helpful for you..

Answer 2

Answer:

d} not defined

Step-by-step explanation:

Given,

In triangle ABC,

m∠C = 90°,

∵ Sum of all interior angles of a triangle is 180°,

⇒ m∠A + m∠B + m∠C = 180°,

⇒ m∠A + m∠B = 180° - m∠C = 180° - 90° = 90°

Thus, sec(A+B) = sec (90°) = $\frac{1}{cos 90^{\circ}}$ = $\frac{1}{0}$ = ∞

( Since, sec x = 1 / cos x and cos 90° = 0 )

Hence, OPTION d is correct.