Question

If triangle ABC is right angled at C, then the value of sec (A+B) is
a) 0
b) 1
d) not defined​

Answer 1

Answer:

d) not defined I think so

Answer 2

Answer:

d) not defined.

Step-by-step explanation:

Given that the triangle ABC is right-angled and ∠C is 90°.

We know that the sum of all three angles of a triangle is always 180°.

Hence, ∠A +∠B +∠C =180°

⇒ ∠A +∠B =180°-∠C= 180°-90° =90°........ (1)  

{Since already it is given that ∠C=90°}

Then, Sec (A+B)= Sec(∠A+∠B)= Sec 90° [ from equation (1)]

⇒ Sec (A+B) =1/Cos 90° =1/0= not defined. (Answer)

{We know that the value of Cos 90°=0}