Question

If triangle ABC is right angled triangle at B ,AB=35 and BC=12 .Find the value of sinA(1) cosA (2) sinC(3)cosC(4)​

Answer 1

Answer:

Step-by-step explanation:

Given ABC is a right-angled triangle at B, ∠B = 90°

So AC is the hypotenuse

Given sides AB = 35cm and BC = 12cm

We know that,

By Pythagoras theorem,

        AC² = AB² + BC²

     ⇒AC² = 35² + 12²

               = 1225 + 144

               =1369

∴ AC = √1369 = 37

Opposite angle of BC is ∠A

Opposite angle of AC is ∠B

Opposite angle of AB is ∠C

So,

1. sinA = oppostie side/hypotenuse

          =BC/AC

          =12/37

2.cosA = adjacent side/hypotenuse

            = AB/AC

           = 35/37

3. sinC = opposite side/hypotenuse

           = AB/AC

           = 35/37

4.cosC = adjacent side/hypotenuse

            = BC/AC

            = 12/37