Question

if triangle ABC is right angled triangle at C then the value of cos(A+B) is

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Answer 1

Answer:

IF TRIANGLE ABC IS RIGHT ANGLED TRIANGLE AT C THEN THE VALUE OF COS (A +B) IS =0

BELOW IS THE EXPLANATION

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Step-by-step explanation:

We know that the sum of all 3 angles in a triangle is 180° .

C=90°

But,

A+B+C=180°

⟹A+B=(180−90)°=90°

We also know that cos90°=0

Hence,

cos(A+B)=0

Answer 2

Answer:

Step-by-step explanation:

IF TRIANGLE ABC IS RIGHT ANGLED TRIANGLE AT C THEN THE VALUE OF COS (A +B) IS =0

BELOW IS THE EXPLANATION

PLEASE FOLLOW ME AND MARK ME AS BRAINLIEST

Step-by-step explanation:

We know that the sum of all 3 angles in a triangle is 180° .

C=90°

But,

A+B+C=180°

⟹A+B=(180−90)°=90°

We also know that cos90°=0

Hence,

cos(A+B)=0