if triangle ABC is similar to triangle DEF and 3AB=5DE and DF=9cm,find AC
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3AB=5DE
3/5=DE/AB
Now we use the formula of similarity of triangle.
DE=3, AB=5, DF=9
AB/DE=AC/DF
5/3=AC/9
5×9/3=AC
AC=15.
Hope this answer is helpful
3/5=DE/AB
Now we use the formula of similarity of triangle.
DE=3, AB=5, DF=9
AB/DE=AC/DF
5/3=AC/9
5×9/3=AC
AC=15.
Hope this answer is helpful
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