Question

if triangle ABC is similar to triangle DEF such that 2AB=DE.and BC=8cm.find EF

Answer 1

As, triangle ABC and DEF r similar .....  and DE = 2AB and BC = 8 cm .........

then according to sides theorem :-

AB / DE = BC / EF

----> AB / 2AB = BC / EF  [as DE = 2AB]

----> 1 / 2 = BC / EF

----> EF = 2BC

----> EF = 2 * 8 = 16 cm .........(ans) ...

Hope this helps !!

Answer 2

When two triangles are similar to each other, then

• Corresponding angles of the triangles are equal

•    Corresponding sides of  the triangles are in  proportion

There are two triangles ΔABC and ΔDEF then they are similar .

according to sides theorem :-

AB / DE = BC / EF

∴AB/2AB​=BC /EF​        ​[∵DE=2AB]

⇒$\frac{1}{2}$ =  $\frac{BC}{EF}$

EF = 2BC

EF = 2 ×8 = 16cm             [ BC = 8cm]

Hence EF = 16cm.

Ans :- EF = 16cm.

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