If triangle ABC is similar to triangle DEF such that 2AB = DE and BC = 8 cm, then find the length of EF.
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By using properties of similar triangles we get EF=16cm
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given : ∆ABC ~ ∆DEF
DE = 2AB and BC = 8 cm
therefore, AB/DE = BC/EF
=> AB/2AB = 8/EF [since, DE=2AB]
=> 1/2=8/EF
therefore , EF= 16 cm
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