Question

If triangle abc is similar to triangle def, then show that perimeter of abc / perimeter of def = AB/DE = BC/EF = AC/DF

Answer 1

Answer:

we know that at triangleABC/DEF=(AB/DE)²

we know this by area theorem hence perimeter is √(AB/DE)²

which is AB/DE which is also Whit tall to other corresponding sides.

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