If triangle ABC is similar to Triangle PQR is median is similar to the values
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Answer:
Given:
Triangle ABC is similar to triangle PQR.
Concept used:
If Δ ABC ∼ Δ PQR
Then, (AB/PQ) = (BC/QR) = (AC/PR)
Calculations:
F1 Harshit 13.1.21 Pallavi D1
(AB/PQ) = (BC/QR)
So, (2BD/2QS) = (AB/PQ) (since D and S are midpoints)
⇒ (BD/QS) = (AB/PQ)
⇒ BD × PQ = AB × QS
∴ BD × PQ = AB × QS.
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