Question

If triangle ABC isright angled at C , then the value of sec (A+B) is a) 0. b)1. c)2/√3. d)not defined. PLEASE ANSWER WITH CORRECT EXPLANATION​

Answer 1

Answer:

not defined.

Step-by-step explanation:

A+B+C=180°.

A+B=90° (C=90°).

So, Sec (A+B)= Sec90°.

we know that, sec =1/cos...

so, 1/cos(A+B)=1/0.

therefore, it's not defined.