Question

if ∆triangle ABC~∆RSM and if AB=10,BC=12,RS=5 find SM​

Answer 1

Answer:

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Answer 2

$\huge\mathbf{Answer}$

Given

$∆ABC\sim ∆RSM$ ,AB = 10cm, BC = 12cm, RS = 5cm.

To Find:- SM = ?

We know that:

In a pair of similar triangles, the corresponding sides are proportional.

$\dfrac{AB} {RS}\:=\:\dfrac{BC} {SM}\:=\:\dfrac{AC} {RM}$

$\dfrac{10} {5}\:=\:\dfrac{12} {SM}$[Don't take AC and RM side]

$SM\:=\:\dfrac{12 ×5} {10}$

$SM\:=\:6cm$

Therefore, SM Is 6cm.