Question

if triangle ABC similae to triangle PQR And area of triangle ABC = 80 & area of triangle PQR = 125 then find AB/PQ​

Answer 1

AB/PQ = root(80/125) = root(16/25) = 4/5
[ ar(ABC)/ar(PQR) = AB^2/PQ^2 = BC^2/QR^2 =AC^2/PR^2]