Math, asked by alangeorgejohn20, 5 months ago

If triangle ABC similar to triangle DEF such that 2AB=DE and BC=8cm.Find he length of EF​

Answers

Answered by Anonymous
10

Answer:

ANSWER

Given,

ΔABC∼ΔDEF

DE=2AB and BC=8 cm

DE

AB

=

EF

BC

2AB

AB

=

EF

8

[∵DE=2AB]

2

1

=

EF

8

∴EF=16 cm

Answered by Anonymous
2

Answer:

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