If triangle ABC similar to triangle DEF such that 2AB=DE and BC=8cm.Find he length of EF
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Given,
ΔABC∼ΔDEF
DE=2AB and BC=8 cm
∴
DE
AB
=
EF
BC
⇒
2AB
AB
=
EF
8
[∵DE=2AB]
⇒
2
1
=
EF
8
∴EF=16 cm
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