if triangle ABC similar to triangle pqr , area of triangle ABC is 80 and area of triangle pqr is 125 then find ab and pq
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ab/pq=4/5 is the answer
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Given,
ΔABC ≈ ΔPQR.
ΔABC area = 80cm².
ΔPQR area =125cm².
To Find,
The sides AB and PQ.
Solution,
Given that,
ΔABC ≈ ΔPQR
Area of ΔABC = 80cm²
Area of ΔPQR = 125cm²
The triangles are similar.
The area of the triangle's ratio is equal to the ratio of the square of the sides.
=
80/125 = AB²/PQ²
AB²/PQ² = 16/25
AB²/PQ² = 4²/5²
AB/PQ = 4/5
Therefore,
AB = 4cm
PQ = 5cm
Hence, the side AB is 4cm and PQ is 5cm.
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