If triangle ABC similar to triangle RPQ AB =3CM,BC=5CM,AC=6CM,RP=6CM N and PQ=10CM then find QR
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Ab is 3cm BC is 5cm ac is 6cm rp is 6cm pq is 10cm the rq will be 12cm
Ab is 3cm BC is 5cm ac is 6cm rp is 6cm pq is 10cm the rq will be 12cm
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Given,
Two triangle Δ ABC, ΔRPQ.
ΔABC ≈ ΔRPQ
AB = 3cm
BC = 5cm
AC = 6cm
RP = 6cm
PQ = 10cm
To Find,
The side QR in the Δ RPQ.
Solution,
Given that,
There are two triangles Δ ABC and ΔRPQ.
Both the triangles are similar.
Two triangles are similar when all the sides of the triangles are proportional.
Therefore,
AB is proportional to RP.
BC is proportional to PQ.
AC is proportional to RQ.
= =
6/3 = 10/5 = RQ/6
=
RQ = (10*6) / 5
RQ = 12cm.
In ΔRPQ, the side RQ is 12cm.
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