Question

if triangle ABC~ triangle DEF such that area of triangleABC is 9cm^2 and the area of triangleDEF is 16cm^2 and BC=2.1. find the length of EF​

Answer 1

Step-by-step explanation:

Here,triangleABC ~ triangle DEF

Therefore,

BC/EF = AC/DF = AB/DE

Then,

ar(triangleABC)/ ar(triangleDEF) = 16/9

(BC/EF)^ = 16/9

(2.1/EF)^ =16/9

EF^=16×2.1^/9

EF=2.8cm

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Answer 2

Answer:

given : triangle ABC= 9cm^2

triangle DEF = 16^2

BC =2.1

to find: length of E F

ABC/ DEF = BC^2/EF^2

9/16 = 2.1^2 / EF ^2

3/4 = 2.1/EF

EF = 2.8

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