If triangle ABC ~triangle DEF, the perimeter of triangle DEF is 20 cm, if one side of triangle ABC is 12cm.
If corresponding side of triangle DEF is 8 cm then perimeter of triangle ABC is
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Answer:
ABC ~ DEF
AB/DE =BC/EF = AC/DF =( AB+BC+CA)/(DE+EF+FD)
AB/DE = perimeter of ABC / perimeter of DEF
12/8= P(ABC)/20
P(ABC)= (12/8)×20
=30
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