Question

if triangle abc- triangle edc ac- 15, bc- 12 , cd- १२ then find cd
​

Answer 1

by ratio of corresponding side

of similar triangle

AB/ED =BC/CD =AC/CE

BC/CD =AC/CE

10/CD=15/12

10×12=15×CD. cross multiplication

120/15=CD

CD=8

Hence CD = 8