Question

 *If triangle ABC ~triangle PQR and angle A = 40°,angle B = 50° then angle R = *​

Answer 1

Answer:

Angle R = 90°

explanation:

Angle A + Angle B + Angle C = 180°- (Sum of all angles

triangle is 180°)

40°+ 50° + Angle C = 180°

90° + Angle C = 180°

Angle C = 180°-90°

Angle C = 90°

∆ ABC~ ∆ PQR

THEREFOR, ANGLE C= ANGLE R= 90°

Answer 2

Given :  ΔABC  ~  Δ PQR

∠A = 40°

∠B = 50°

To Find : ∠R

Solution:

ΔABC  ~  Δ PQR

Corresponding angles of similar triangles are equal in measure

=> ∠A = ∠P

  ∠B = ∠Q

∠A = 40°  => ∠P =   40°

∠B = 50°   => ∠Q =  50°

Sum of measures of  angles of a triangle is 180°

∠P + ∠Q + ∠R =  180°

Substitute ∠P =   40°  and   ∠Q =  50°

=> 40°  + 50° + ∠R =  180°

=>  90° + ∠R =  180°

=>  ∠R =  180° - 90°

=> ∠R =  90°

Correct answer is   ∠R =  90°

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