IF TRIANGLE ABC ~= TRIANGLE PQR AND ANGLE A = 65°, angle B =45° then angle R is
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Answer:70°
Step-by-step explanation:
Given,Δ ABC≅ Δ PQR
therefore, ∠A=∠P=65°
∠B=∠Q=45°
∠C=∠R=?
In ΔABC,
∠A+∠B+∠C=180°(Angle Sum Property of Triangle)
65°+45°+∠C=180°
110°+∠C=180°
∠C=180°-110°
∠C=70°
Since ∠C=∠R
∠R=70°
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