if triangle ABC~triangle QRP,ar(Triangle ABC)/ar(triangle QRP)=9/4,BC=15 cm,then find PR
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Heya your answer is
Given :
Area of ∆ ABCArea of ∆QRP = 94
AB = 18 cm , BC = 15 cm So PR = ?
We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.
Area of ∆ ABCArea of ∆ QRP = AB2QR2 = BC2PR2 = AC2QP2
So , we take
Area of ∆ ABCArea of ∆ QRP = BC2PR2
Now substitute all given values and get
94 = 152PR2
Taking square root on both hand side , we get
32 = 15PR
PR = 10 cm
hope it may help you........
please mark it as brainliest.....
Given :
Area of ∆ ABCArea of ∆QRP = 94
AB = 18 cm , BC = 15 cm So PR = ?
We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.
Area of ∆ ABCArea of ∆ QRP = AB2QR2 = BC2PR2 = AC2QP2
So , we take
Area of ∆ ABCArea of ∆ QRP = BC2PR2
Now substitute all given values and get
94 = 152PR2
Taking square root on both hand side , we get
32 = 15PR
PR = 10 cm
hope it may help you........
please mark it as brainliest.....
siddhi123456:
It's right
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