if triangle ABE~= triangle ACD , show that triangle ADE~ triangle ABC.
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Answered by
49
if ΔABE=ΔACD,
⇒∠B=∠C &∠E=∠D(by cpct)
And we know ∠A=∠A
therefore,
∠A/∠A=∠B/∠D/∠E=1
hence proved
⇒∠B=∠C &∠E=∠D(by cpct)
And we know ∠A=∠A
therefore,
∠A/∠A=∠B/∠D/∠E=1
hence proved
anne9:
by which criterion ????
none of them my friend
if 2 triangles have to be proved similar,either ratio of their sides or that of their angles should be equal
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11
See the pic to understand
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