if triangle CAT similar triangle ODG,CA =24cm and ar (CAT):at(ODG)=16:9,then the length of OD is
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length of OD is 18 CM. it can be solved by the relationship of ratio of areas to that of sides in similar triangles
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Given,
Cat ~ Odg
Ca = 24 cm
ar (cat) = ar (odg) = 16:9
•°• ar (Cat)2 = (Ca)2 = (At)2 = (Ct)2.
------- --------- ------- --------
(Odg) (Og) (Dg) (Og)
Ar (Cat) = Ar(Odg) = 16:9
16/9 = (24/Od)2
root 16/9 = 24/Od
=4/3 = 24/od
od = 18
Cat ~ Odg
Ca = 24 cm
ar (cat) = ar (odg) = 16:9
•°• ar (Cat)2 = (Ca)2 = (At)2 = (Ct)2.
------- --------- ------- --------
(Odg) (Og) (Dg) (Og)
Ar (Cat) = Ar(Odg) = 16:9
16/9 = (24/Od)2
root 16/9 = 24/Od
=4/3 = 24/od
od = 18
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